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-4x^2+23x+72=0
a = -4; b = 23; c = +72;
Δ = b2-4ac
Δ = 232-4·(-4)·72
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-41}{2*-4}=\frac{-64}{-8} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+41}{2*-4}=\frac{18}{-8} =-2+1/4 $
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